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What is the Solution of a Radical Equation?

Grade Level:

Class 10

AI/ML, Physics, Biotechnology, Space Technology, Chemistry, Engineering, Medicine

Definition
What is it?

The solution of a radical equation is the value or values of the variable that make the equation true. It's like finding the 'secret number' that balances both sides of an equation involving square roots, cube roots, or other roots.

Simple Example
Quick Example

Imagine you have a puzzle: 'The square root of a number, plus 3, equals 5.' What is that number? We need to find the number (let's call it 'x') such that sqrt(x) + 3 = 5. The solution here would be x = 4, because sqrt(4) = 2, and 2 + 3 = 5.

Worked Example
Step-by-Step

Solve the radical equation: sqrt(x - 2) = 4

1. Isolate the radical term: The radical term, sqrt(x - 2), is already by itself on one side.
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2. Square both sides of the equation to remove the square root: (sqrt(x - 2))^2 = 4^2
This simplifies to x - 2 = 16
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3. Solve the resulting linear equation for x: Add 2 to both sides: x - 2 + 2 = 16 + 2
So, x = 18
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4. Check your solution by substituting it back into the original equation: sqrt(18 - 2) = 4
sqrt(16) = 4
4 = 4 (This is true, so our solution is correct.)

Answer: The solution is x = 18.

Why It Matters

Understanding radical equations is crucial for designing everything from satellite orbits in Space Technology to calculating medication dosages in Medicine. Engineers use them to model how structures behave, and physicists apply them to understand energy and motion. It's a fundamental skill for many advanced scientific and technical careers.

Common Mistakes

MISTAKE: Squaring only part of one side of the equation, e.g., in (sqrt(x) + 3) = 5, students might write x + 9 = 25. | CORRECTION: When squaring an entire side that has multiple terms, remember to square the entire expression, not just individual terms. For (sqrt(x) + 3)^2, it would be (sqrt(x))^2 + 2*sqrt(x)*3 + 3^2, which is x + 6sqrt(x) + 9.

MISTAKE: Forgetting to check for extraneous solutions. After solving, students might assume all answers are valid. | CORRECTION: Always substitute your found solutions back into the original radical equation. If a solution makes the original equation false (e.g., results in a square root of a negative number on the real number line, or an inequality), it is an extraneous solution and must be discarded.

MISTAKE: Not isolating the radical before squaring. Students might square too early, making the equation more complex. | CORRECTION: Always get the radical term by itself on one side of the equation before squaring or raising to any power. This makes the squaring step simpler and more effective.

Practice Questions
Try It Yourself

QUESTION: Solve sqrt(y + 5) = 3 | ANSWER: y = 4

QUESTION: Solve sqrt(2m - 1) - 4 = 1 | ANSWER: m = 13

QUESTION: Solve sqrt(x + 7) = x - 5 | ANSWER: x = 9 (Note: x = 2 is an extraneous solution)

MCQ
Quick Quiz

Which of the following is a solution to the equation sqrt(x) + 2 = 6?

x = 2

x = 4

x = 16

x = 8

The Correct Answer Is:

C

To solve sqrt(x) + 2 = 6, first subtract 2 from both sides to get sqrt(x) = 4. Then, square both sides: (sqrt(x))^2 = 4^2, which gives x = 16. So, option C is correct.

Real World Connection
In the Real World

Radical equations are used by engineers at ISRO (Indian Space Research Organisation) to calculate the escape velocity needed for a rocket to leave Earth's gravity. They also help mobile app developers determine the optimal range for Wi-Fi signals, which often involves square root functions based on signal strength and distance.

Key Vocabulary
Key Terms

RADICAL: The symbol (like sqrt) used to denote a root of a number | EXTRANEOUS SOLUTION: A solution obtained during the solving process that does not satisfy the original equation | RADICAL EQUATION: An equation where the variable is inside a radical symbol | ISOLATE: To get a term by itself on one side of an equation

What's Next
What to Learn Next

Now that you know how to solve radical equations, you can explore quadratic equations, which sometimes arise after squaring radical equations. You'll also be ready for more complex functions involving roots in higher classes!

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