Let's say a digital forensic team is investigating a cyber-crime. They have data showing a suspect's laptop connected to two different Wi-Fi routers. Router A is at coordinates (0,0) and Router B is at (100,0) meters (imagine a map). The laptop's signal strength indicates it was 80 meters from Router A and 60 meters from Router B. We need to find the laptop's position.

1. **Understand the setup:** We have two fixed points (routers) and distances to a third unknown point (laptop).
2. **Formulate equations (using distance formula):** Let the laptop's position be (x,y).
Distance from Router A (0,0) to (x,y) is 80m: x^2 + y^2 = 80^2 = 6400
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3. **Distance from Router B (100,0) to (x,y) is 60m:** (x-100)^2 + y^2 = 60^2 = 3600
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4. **Expand the second equation:** x^2 - 200x + 10000 + y^2 = 3600
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5. **Substitute x^2 + y^2 from the first equation into the expanded second equation:**
6400 - 200x + 10000 = 3600
16400 - 200x = 3600
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6. **Solve for x:**
200x = 16400 - 3600
200x = 12800
x = 12800 / 200
x = 64
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7. **Substitute x back into the first equation to find y:**
64^2 + y^2 = 6400
4096 + y^2 = 6400
y^2 = 6400 - 4096
y^2 = 2304
y = sqrt(2304)
y = 48 (we take the positive value for simplicity, assuming it's in the first quadrant)
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8. **Result:** The laptop's estimated position is (64, 48). This uses basic geometry and algebra, which are the building blocks for more complex trigonometric calculations in real scenarios.

**Answer:** The laptop's estimated position is (64, 48).